Is it possible to transmit some information faster than light and to modify the past ? These problems are raised by the following thought experiment : Screen | | | | Slit 1 | +--------------+ | | | Measurement | | | <- * -> | device / on| | | Source | off| | +--------------+ | | Slit 2 | | A source emits pairs of particles in opposite directions. The particles on the left goes through 2 slits to the screen. The particles on the right goes to a measurement device which records their directions and keep the recording confined in the box in such a way that no information concerning this recording goes out of the box. First the measurement device is turned off, and the source is turned on. The experimentator can see interference fringes on the screen. Then the measurement device is turned on. The experimentator goes on watching at the screen. Then he opens the measurement device and look at the recording of the direction of the particles. - When the measurement device is turned off, does the interference fringes disappear immediately ? Is there some information transmitted faster than light from the measurement device to the screen ? - If not, what happens when the experimentator looks at the recording in the measurement device ? Does it acts bact on the past, creating a world in which there are no interference fringes ? - According to the theory of relativity, faster than light transmission is equivalent to transmission to the past. What happens if we send to the past an information different from the one we received ? - What happens if we decide to look at the recording if we see interference fringes, and to erase it if we don't see fringes ? - How could this experiment be interpreted in terms of Many-Worlds interpretation ? According to Michael Clive Price's Everett FAQ (http://www.hedweb.com/manworld.htm) "The splitting is a local process that is causally transmitted from system to system at light or sub-light speeds" Does this mean that as long as the measurement information is kept in the device, the splitting is confined in the device, so concerning the outside of the device, it is like if the measurement has not been done ? Let us consider a point X located on a dark fringe. According to the Many-Worlds interpretation, there is one world in which the particle reaches X through slit 1 with amplitude Psi, an d one world in which it reaches X through slit 2 with amplitude -Psi, and the total makes 0, so this world is never observed. But what happens if some recording of which slit the particles went through is kept ? Does these two opposite worlds still annihilate them mutually ? Do they become observable only when the experimentator looks at the recording ? - How could this experiment be described with Dirac brackets notation ? Let |X> represent the state in which a particle reaches a point X located on a dark fringe, |S1> the state of the device recording that the particle goes through slit 1, and |S2> same for slit 2. Then if we consider only this point X we would get 1/sqrt(2) * (|X>|S1> - |X>|S2>). If we ignore |S1> and |S2> we get 1/sqrt(2) * (|X> - |X>) = 0, which indicates that the particle never reaches X. The problem with this notation is that a state such as |X>|S1> puts together states of components |X> and |S1> located in different points of space. How can we describe this composed state at instant t ? It is the tensorial product of states of components AT THE SAME TIME t, but this means nothing in the absolute according to the theory of relativity, since the notion of simultaneity is not absolute but depends on the movement. I would appreciate if you have some ideas about these problems. Jacques. Visit my homepages : http://www.byoc.com/homepage/134885/ http://www.chez.com/log/ http://members.rotfl.com/log/